In mathematics, Pascal’s triangle is a triangular array of the binomial coefficients.
The rows of Pascal’s triangle are conventionally enumerated
starting with row n = 0
at the top (the 0th
row). The
entries in each row are numbered from the left beginning
with k = 0
and are usually staggered relative to the
numbers in the adjacent rows. The triangle may be constructed
in the following manner: In row 0
(the topmost row), there
is a unique nonzero entry 1
. Each entry of each subsequent
row is constructed by adding the number above and to the
left with the number above and to the right, treating blank
entries as 0
. For example, the initial number in the
first (or any other) row is 1
(the sum of 0
and 1
),
whereas the numbers 1
and 3
in the third row are added
to produce the number 4
in the fourth row.
The entry in the nth
row and kth
column of Pascal’s
triangle is denoted .
For example, the unique nonzero entry in the topmost
row is .
With this notation, the construction of the previous paragraph may be written as follows:
for any non-negative integer n
and any
integer k
between 0
and n
, inclusive.
We know that i
-th entry in a line number lineNumber
is
Binomial Coefficient C(lineNumber, i)
and all lines start
with value 1
. The idea is to
calculate C(lineNumber, i)
using C(lineNumber, i-1)
. It
can be calculated in O(1)
time using the following:
C(lineNumber, i) = lineNumber! / ((lineNumber - i)! * i!)
C(lineNumber, i - 1) = lineNumber! / ((lineNumber - i + 1)! * (i - 1)!)
We can derive following expression from above two expressions:
C(lineNumber, i) = C(lineNumber, i - 1) * (lineNumber - i + 1) / i
So C(lineNumber, i)
can be calculated
from C(lineNumber, i - 1)
in O(1)
time.